{"id":1831,"date":"2016-11-21T13:28:21","date_gmt":"2016-11-21T12:28:21","guid":{"rendered":"http:\/\/www.supagro.fr\/wordpress\/modeleco\/?page_id=1831"},"modified":"2019-06-19T14:43:38","modified_gmt":"2019-06-19T12:43:38","slug":"activite-15-exploitation-laitiere-solution","status":"publish","type":"page","link":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/auto-formation\/sequence2\/cours2-des-specificites-du-modele-agricole\/lecon-15-l-elevage\/activite-15-exploitation-laitiere-solution\/","title":{"rendered":"Activity 16 : Dairy farm \u2013 Solution Part A"},"content":{"rendered":"<p>The farmer chooses to feed his herd with the \u201cgrass-based\u201d diet. He has around 43 cows and therefore 13 heifers and 26 calves. He grows 26 ha of wheat, 4 ha of maize and 19 ha of grassland. All his wheat production gets sold.<\/p>\n<p>The optimum number of animas is as follows :<\/p>\n<table width=\"198\">\n<tbody>\n<tr>\n<td width=\"102\">Dairy cow<\/td>\n<td width=\"96\">42.857<\/td>\n<\/tr>\n<tr>\n<td width=\"102\">Heifers (alive)<\/td>\n<td width=\"96\">12.857<\/td>\n<\/tr>\n<tr>\n<td width=\"102\">Calves (sold)<\/td>\n<td width=\"96\">25.714<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Optimum cropping pattern is as follows :<\/p>\n<table width=\"194\">\n<tbody>\n<tr>\n<td width=\"97\">Wheat<\/td>\n<td width=\"96\">26.104 ha<\/td>\n<\/tr>\n<tr>\n<td width=\"97\">Maize<\/td>\n<td width=\"96\">3.896 ha<\/td>\n<\/tr>\n<tr>\n<td width=\"97\">Grassland<\/td>\n<td width=\"96\">19.286 ha<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Income is as follows \u00a0: 56 629.87\u20ac.<\/p>\n<p>Checking the number of animals present and the renewal and culling rates :<\/p>\n<p>0.3 * 42.857\u00a0 = 12.857<br \/>\n0.6 * 42.857 = 25.714<\/p>\n<p>Checking whether the food needs are covered by the arable land production :<\/p>\n<p>With 19ha of grassland he produces\u00a0:<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Grazing: 5*19.286 = 96.43 T<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Hay : 4.5*19.286 = 87.787 T<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Wrapped bales : 2.2*19.286 = 42.42 T<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Maize : 11*3.896 = 42.86 T<\/p>\n<p>To feed his animals, he needs :<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Grazing : 1.5*42.857 + 12.857*2.5 = 96.43 T<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Hay : 2*12.857=25.714 T<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Wrapped bales : 2.6*12.857=33.4282 T<br \/>\n<em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>\u00a0Maize : 1*42.857=42.857 T<\/p>\n<p>Production is therefore much more significant than needs.<\/p>\n<p>The solution model is as follows :\u00a0<a href=\"https:\/\/www.supagro.fr\/ModelEco\/en\/modeles\/modelEco_dairyFarm_1.zip\">modelEco_dairyFarm_1.gms<\/a><\/p>\n<p><a href=\"http:\/\/www.supagro.fr\/wordpress\/modelecoen\/auto-formation\/sequence2\/cours2-des-specificites-du-modele-agricole\/\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4121 alignright\" src=\"http:\/\/www.supagro.fr\/wordpress\/modelecoen\/files\/2018\/11\/backUnit.png\" alt=\"\" width=\"211\" height=\"66\" \/><\/a><a href=\"http:\/\/www.supagro.fr\/wordpress\/modelecoen\/auto-formation\/sequence2\/cours2-des-specificites-du-modele-agricole\/lecon-15-l-elevage\/activite-16-modele-elevage-laitier-ecrire-un-modele-delevage-laitier-2\/\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-4326 alignleft\" src=\"http:\/\/www.supagro.fr\/wordpress\/modelecoen\/files\/2018\/11\/backStatement.png\" alt=\"\" width=\"191\" height=\"61\" \/><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>The farmer chooses to feed his herd with the \u201cgrass-based\u201d diet. He has around 43 cows and therefore 13 heifers and 26 calves. He grows 26 ha of wheat, 4 ha of maize and 19 ha of grassland. All his <a class=\"more-link\" href=\"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/auto-formation\/sequence2\/cours2-des-specificites-du-modele-agricole\/lecon-15-l-elevage\/activite-15-exploitation-laitiere-solution\/\">Continue reading <span class=\"screen-reader-text\">  Activity 16 : Dairy farm \u2013 Solution Part A<\/span><span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":92,"featured_media":0,"parent":1497,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-1831","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/pages\/1831","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/users\/92"}],"replies":[{"embeddable":true,"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/comments?post=1831"}],"version-history":[{"count":20,"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/pages\/1831\/revisions"}],"predecessor-version":[{"id":4596,"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/pages\/1831\/revisions\/4596"}],"up":[{"embeddable":true,"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/pages\/1497"}],"wp:attachment":[{"href":"https:\/\/www.supagro.fr\/wordpress\/modelecoen\/wp-json\/wp\/v2\/media?parent=1831"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}