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You modelled the problem below in step 3 (or you can download it here modelEco_familyFarm_3.zip) :
« A farmer owns 5 ha of land. His family can provide the equivalent of 5 people per year in terms of working time. The number of working days per year and per person is estimated at 100. This farmer can choose between 4 agricultural activities whose costs, yields and prices are shown in the table below. The currency is the rupee.
1. ACTIVITIES | 2. Wheat | 3. Rice | 4. Sugar cane | 5. Livestock |
6. YIELD (Tons/ha or Rupees/ha for livestock) |
7. 9 | 8. 6 | 9. 18 | 10. 17000 |
11. COSTS (Rupees/ha) | 12. 3120 | 13. 5480 | 14. 11360 | 15. 5000 |
16. PRICE(Rupees/ton) | 17. 990 | 18. 3276 | 19. 1686 | 20. 1 |
For livestock, the value shown in the yield line directly measures the gross product per hectare. A value of 1 was therefore provided in the price line.
The table below compiles the resource needs for each activity.
ACTIVITIES | Wheat | Rice | Sugar cane | Livestock |
Labour(days/year/ha) | 40.5 | 96 | 282 | 159 |
Water (m3/ha) | 740 | 3000 | 2200 | 1100 |
Land (ha) | 1 | 1 | 1 | 1 |
The objective of the farmer is to maximize the global gross margin.
The State reinforces the law concerning water consumption and imposes a 7000 m3 limit per farm. It is possible to buy irrigation water at 2 rupees per m3 . »
The farmer’s lack of money (available cashflow constraint) must be taken into account, so that total crop costs must not exceed 20 000 rupees. Modify the model and answer the questions.
If you need help and/or to make sure you use the same name for the data :
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In order to maximize his gross margin, while taking into account the cashflow constraint, the farmer will dedicate :
ACTIVITIES Wheat Rice Sugar cane Livestock Optimum area (ha) 0.40 1.44 0 2.18 His income would be 48791 rupees.
If you did not answer all the questions correctly, click on “view questions”. Dowload the following solution model to see how to add the new constraint in question : modelEco_familyFarm_4.zip.
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Question 1 of 7
1. Question
You modelled the problem below in step 3 (or you can download it here modelEco_familyFarm_3.zip) :
« A farmer owns 5 ha of land. His family can provide the equivalent of 5 people per year in terms of working time. The number of working days per year and per person is estimated at 100. This farmer can choose between 4 agricultural activities whose costs, yields and prices are shown in the table below. The currency is the rupee.
1. ACTIVITIES 2. Wheat 3. Rice 4. Sugar cane 5. Livestock 6. YIELD
(Tons/ha or
Rupees/ha for livestock)7. 9 8. 6 9. 18 10. 17000 11. COSTS (Rupees/ha) 12. 3120 13. 5480 14. 11360 15. 5000 16. PRICE(Rupees/ton) 17. 990 18. 3276 19. 1686 20. 1 For livestock, the value shown in the yield line directly measures the gross product per hectare. A value of 1 was therefore provided in the price line.
The table below compiles the resource needs for each activity.
ACTIVITIES Wheat Rice Sugar cane Livestock Labour(days/year/ha) 40.5 96 282 159 Water (m3/ha) 740 3000 2200 1100 Land (ha) 1 1 1 1 The objective of the farmer is to maximize the global gross margin.
The State reinforces the law concerning water consumption and imposes a 7000 m3 limit per farm. It is possible to buy irrigation water at 2 rupees per m3 . »
The farmer’s lack of money (available cashflow constraint) must be taken into account, so that total crop costs must not exceed 20 000 rupees. Modify the model and answer the questions.
If you need help and/or to make sure you use the same name for the data :How great is the land area dedicated to wheat (in ha) ? Round off to a hundredth.
Correct
Incorrect
0,40 ha
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Question 2 of 7
2. Question
How great is the land area dedicated to rice (in ha) ? Round off to a hundredth.
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Incorrect
1, 44 ha
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Question 3 of 7
3. Question
How great is the land area dedicated to sugar cane (in ha) ? Round off to a hundredth.
Correct
Incorrect
0 ha
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Question 4 of 7
4. Question
How great is the land area dedicated to livestock (in ha) ? Round off to a hundredth
Correct
Incorrect
2,18 ha
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Question 5 of 7
5. Question
How much income is made ? Round off to the nearest rupee.
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Incorrect
48791 rupees
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Question 6 of 7
6. Question
The EauA variable which represents water is equal to 0. Why does the farmer not buy water anymore ?
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Incorrect
False. Adding a cashflow constraint has modified the values of the solutions, notably the marginal value of the irrigation constraint. This marginal value of 1.908 means that the farmer is willing to pay 1.908 additional rupees maximum in order to obtain 1 additional m3 of water. The selling price of a m3 is 2 rupees, it is therefore not in the interest of the farmer to buy any.
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Question 7 of 7
7. Question
If the farmer had 1 additional hectare, by how much would his income increase ? Round off to the nearest rupee.
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Incorrect
False ! The optimal solution suggests a total area of 4.013ha, therefore lower than 5ha. The land constraint is non-binding. An additional hectare would not change the solution and the income of the farmer would remain the same.